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# Answer to Question #140271 in Inorganic Chemistry for Neo

Question #140271
3. A closed system initially containing 1.000 × 10-3 M H2 and 2.000 × 10-3 M I2 at 448℃ is allowed to reach equilibrium. At equilibrium, the HI concentration is 1.87 × 10-3 M. Given that the reaction equation is H2(g) + I2(g) ↔ 2 HI(g), find:
a. Equilibrium concentrations of the two reactants
b. Kc of the reaction taking place.
1
2020-10-26T14:53:58-0400

"H_2(g) + I_2(g) \u2194 2 HI(g)"

initial concentration

"H_2 =1mM\\\\I_2=2mM"

"HI=0"

at equilibrium let's assume

"H_2 =(1-x)mM\\\\I_2=(2-x)mM\\\\HI=2x"

we are given equilibrium concentration of HI is 1.87mM

"2x=1.87\\\\x=0.935"

at equilibrium,

"H_2" ="1-0.935=0.065mM"

"I_2=2-0.935=1.065mM"

"HI=2\\times0.935=1.87mM"

Kc of the reaction ="\\frac{[HI]^2}{H_2I_2}=\\frac{1.87\\times1.87}{1.065\\times0.065}=50.5"

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