Answer to Question #12549 in Inorganic Chemistry for mass

Question #12549
determine the number of atoms in each of the following 1) 2.85 mol of Ag 2) 12.9g of CaCO3 3) 12.9g of Fe(NO3)3
Expert's answer
The number of particles is
N(particles) =
N(Avogadro)*n(particles)
1)
N(Ag) = 6.022*10^23 mol^-1 * 2.85 mol =
1.72*10^24
2)
The amount of CaCO3 is
n(CaCO3) = m(CaCO3) / M(CaCO3) =
12.9 g / 100 g/mol = 0.129 mol
N(CaCO3) = 6.022*10^23 mol^-1 * 0.129 mol =
7.77*10^22
3)
The amount of Fe(NO3)3 is
n(Fe(NO3)3) = m(Fe(NO3)3) /
M(Fe(NO3)3) = 12.9 g / 242 g/mol = 0.053 mol
N(Fe(NO3)3) = 6.022*10^23 mol^-1
* 0.053 mol = 3.19*10^22

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS
paypal