Answer to Question #119456 in Inorganic Chemistry for Ddd

Question #119456
To neutralize 25 cm3 of 0,20 M KOH you need: a) 25 cm3 of 0,40 M hydrochloric acid b) 20 cm3 of 0,25 M hydrochloric acid c) 50 cm3 of 0,10 M hydrochloric acid d) 25 cm3 of 0,10 M hydrochloric acid e) none
1
Expert's answer
2020-06-04T10:31:07-0400

To neutralize 25 cm3 of 0,20 M KOH you need 0.025L*0.20mol/L=0.005mol of an acid.

This amount of acid is contained in the solution of variants B and C.


The answer: B and C.


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