Answer to Question #118567 in Inorganic Chemistry for josi

Question #118567
how many moles are there in 51.1 g of NH3?
1
Expert's answer
2020-05-28T10:33:48-0400

n(NH3)= m(NH3)/Mr(NH3);

Mr(NH3)=14+3=17 g/mol;

n(NH3)=51.1/17=3 mol;

Answer: 3.0 mol of NH3

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