Answer to Question #11586 in Inorganic Chemistry for swagatika
what will be the volume of ammonia that can be produced out of 2.8g of nitrogen and 44.8l of hydrogen at S.T.P in haber's process
Haber's process: N2 + 3H2 = 2NH3 n(N2) = m(N2) / M(N2) = 2.8g / 28g/mol = 0.1 mol n(H2) = V(H2) / Vm = 44.8L / 22.711L/mol = 1.97 mol The molar volume of an ideal gas at STP (100 kPa and 273.15K) is 22.711 L/mol H2 is the excess reagent, and N2 is the limiting reagent. Thus, the volume of ammonia is V(NH3) = 2*V(N2) = 2*n(N2)*Vm = 2 * 0.1mol * 22.711L/mol = 4.54 L.
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