Question #11415

8g Ca++ contain what number of charges

Expert's answer

The molar mass of Calcium is 40 g/mol

Thus, 8 g of Ca correspond to n(ca) =

mCa)/M(Ca) = 8 g / 40 g/mol = 0.2 mol of Ca.

One Ca++ ion has 2 charges, so

0.2 mol of Ca++ contain 0.4 mol of charges.

One mol of charges contain 96485

coulombs, so 0.4 mol contain n(Ca++) * F = 0.4*96485 = 38594 C.

(F = Faraday

constant is the magnitude of electric charge per mole of electrons, F = 96485

C/mol)

Thus, 8 g of Ca correspond to n(ca) =

mCa)/M(Ca) = 8 g / 40 g/mol = 0.2 mol of Ca.

One Ca++ ion has 2 charges, so

0.2 mol of Ca++ contain 0.4 mol of charges.

One mol of charges contain 96485

coulombs, so 0.4 mol contain n(Ca++) * F = 0.4*96485 = 38594 C.

(F = Faraday

constant is the magnitude of electric charge per mole of electrons, F = 96485

C/mol)

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