Question #113182

When 0.25 L of liquid nitrogen (d = 0.807 g/mL) is vaporized, what volume does the resulting gas occupy at 25 °C and 5.00 atm

Expert's answer

**Solution.**

"p \\times V= \\frac{m}{M}\\times R\\times T"

"V = \\frac{m \\times R \\times T}{p \\times M}"

"V = \\frac{250 \\times 0.807 \\times 8.31 \\times 298}{28 \\times 506625} = 0.03 \\ ml"

**Answer:**

V = 0.03 ml

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