Answer to Question #111525 in Inorganic Chemistry for Jonathan

Question #111525
How many grams of nitric acid can be prepared from the reaction of 138 grams of NO2 with 54 grams of H2O according to the equation: 3NO2 + H2O -> 2HNO3 + NO
1
Expert's answer
2020-04-23T13:08:02-0400

n(NO2) = 138/46 = 3 mol

n(H2O) = 54/18 = 3 mol


water in excess, therefore:


n(HNO3) = n(NO2)*2/3 = 2 mol


m(HNO3) = 2*63 = 126 g

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