# Answer to Question #1091 in Inorganic Chemistry for Thomasina

Question #1091

One method of removing CO

How many liters of CO

_{2}gas from a spacecraft is to allow the CO_{2}to react with LiOH.How many liters of CO

_{2}at 25.9 degrees Celcius and 751 Torr can be removed per kilogram of LiOH consumed?Expert's answer

CO

We have 1kg LiOH : 1000g/(7+16+1) g/mol = 1000/24 = 41.67 mol.

Thus M(CO

m(CO

Use the equation

pV = ν R T

p = 751 torr = 100 125.099 Pa, T = 25.9 C = 298.9 K

V = ν R T / p = 83.33 * 8.31 *298.9 /100125.099 = 2.07 m

_{2}+ 2LiOH = Li_{2}CO_{3}+ H_{2}OWe have 1kg LiOH : 1000g/(7+16+1) g/mol = 1000/24 = 41.67 mol.

Thus M(CO

_{2}) = 2 M(LiOH) = 83.33 molm(CO

_{2}) = 83.33 mol * (12 + 2*16) g/mol = 4000 g = 4 kg.Use the equation

pV = ν R T

p = 751 torr = 100 125.099 Pa, T = 25.9 C = 298.9 K

V = ν R T / p = 83.33 * 8.31 *298.9 /100125.099 = 2.07 m

^{3}= 2067.2 LitersNeed a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment