Answer to Question #99862 in General Chemistry for Cookie

Question #99862
How many grams of solute are present in 845ml of 0.670 M KBr?
1
Expert's answer
2019-12-03T08:26:48-0500

@$c=\frac{n}{V}@$

@$n=c\times V @$


@$n(KBr) = 0.670\times0.845 = 0.5662 mol@$


@$m(KBr)= M\times n = 119.00 \times 0.5662 = 67.37 g@$


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