Answer to Question #99862 in General Chemistry for Cookie

General Chemistry

Question #99862

How many grams of solute are present in 845ml of 0.670 M KBr?

Expert's answer

"c=\\frac{n}{V}"

"n=c\\times V"

"n(KBr) = 0.670\\times0.845 = 0.5662 mol"

"m(KBr)= M\\times n = 119.00 \\times 0.5662 = 67.37 g"

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