Question

If hydrogen gas is collected over water at 26 °C and the total pressure of the gas mixture (hydrogen + water vapor) is found to be 0.986 atm, what is the partial pressure of the hydrogen (in atm) in the mixture?

Answer 1

P= 0.986 atm

P(water vapour) _{at 26°C} = 0.033 atm

P = P (H₂) + P (water vapour)

P(H₂)= P-P(water vapour)=0.086-0.033=0.953 atm