Question

Consider the following equation. HCl (aq) + NaOH (aq) à H2O (l) + NaCl (aq)
If 0.25 moles of sodium hydroxide completely react with hydrochloric acid how many moles of water will be made?

Answer 1

Since all compounds in the reaction have 1 mole, by stiochiometry number of moles of water will be equal to number of moles of sodium hydroxide.

$0.25 moles \cdot \frac {1}{1}=0.25moles$