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Answer to Question #89704 in General Chemistry for Michael

Question #89704
If 8.42 x 10^(24)molecules of ammonium sulphate are allowed to react with excess sodium hydroxide, calculate the volume of ammonia gas produced.
Expert's answer

(NH4)2SO4 + 2NaOH = Na2SO4 + 2NH3 + H2O

n ((NH4)2SO4 = N/Na

n = 8,42•1024 / 6,02•1023 = 13.99 mole

n (NH3) = 27.97 mole

V (NH3) = n×Vm

V (NH3) = 27.97 × 22.4 = 626.6 litre

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