Question #88160
What is the mass of ammonium chloride is 500.0mL of a 0.198M solution?
1
Expert's answer
2019-04-18T05:05:17-0400

500mL=0.5L

n(NH4Cl)=0.5L∗0.198mol/L=0.099moln(NH4Cl)=0.5L*0.198mol/L=0.099mol

53.49g/mol∗0.099moles=5.295g53.49g/mol*0.099moles=5.295g


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