Question #86307

C(s) + 2H2(g) ---> CH4(g)
if the reaction produces 145 liters of CH4, how many liters of H2 were consumed?

Expert's answer

The balanced equation for considered reaction can be written as follows

@$C(s) + 2H_{2}(g) \rarr CH_{4}(g)@$

@$\frac{V(H_{2})}{N(H_{2}) \cdot V_m} = \frac{V(CH_{4})}{N(CH_{4}) \cdot V_m}@$

V - volume

N - coefficient in chemical equation

V_{m} - molar volume

@$V(H_{2}) = \frac{V(CH_{4}) \cdot N(H_{2})}{N(CH_{4})}@$

@$V(H_{2}) = \frac{145 \cdot 2}{1}=290 \; L@$

**Answer:** 290 liters.

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