Question #84149

what is the original amount of Po if 25.0 grams after 5 half lives?

Expert's answer

The radiactive half-life gives a pattern of reduction to half in any successive half-life period.

A=A2^{-t/T}

T-is half-life period

As t=5T then

A=A2^{-5T/T}

25=A2^{-5}

25=A/32

A= 32*25

A=800

Answer: 800 g

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