Answer to Question #83633 in General Chemistry for heather

Question

What is the pressure inside a cylinder when the volume changes from 14.37 dm3 to 49.31 dm3 with an initial pressure of 9.021 x 102 kPa? The temperature of the cylinder remained constant at 22.06ºC.

Answer 1

Answer on Question #83633, Chemistry/ General Chemistry

What is the pressure inside a cylinder when the volume changes from 14.37 dm3 to 49.31 dm3 with an initial pressure of 9.021 x 102 kPa? The temperature of the cylinder remained constant at 22.06ºC.

Solution

As temperature remained constant at 22.06C we can use Boyle's Law to find the final pressure incide a cylinder:

P₁V₁ = P₂V₂

where P₁ = 9.021*10² kPa = 902.1 kPa

V₁ = 14.37 dm³

V₂ = 49.31 dm³

902.1*14.37 = P₂*49.31

P₂ = 262.9 kPa = 2.629*10² kPa

Answer: 2.629*10² kPa