Answer to Question #72657 in General Chemistry for Chloe Lozano

Question

A gas grill burns Propane (C3H8) in the presence of more than sufficient Oxygen (O2). This reaction produces water vapor and Carbon Dioxide. The temperature and pressure conditions are such that 1 mole of each gas occupies 1 liter of volume.

If 15 liters of Propane are completely consumed, how many grams of Propane were there?

A. 40.08 g Propane
B. 80.16 g Propane
C. 160.32 g Propane
D. 320.64 g Propane
E. None of the Above

Answer 1

Solution
If there were 15 litres of propane and 1 mole of each gas occupies 1 liter of volume then we can say that we had 15 moles of propane.
m=nM=15*44,1=661.5 of Propane.
Answer: E. None of the Above