A gas grill burns Propane (C3H8) in the presence of more than sufficient Oxygen (O2). This reaction produces water vapor and Carbon Dioxide. The temperature and pressure conditions are such that 1 mole of each gas occupies 1 liter of volume.
If 15 liters of Propane are completely consumed, how many liters of water vapor will be produced?
A. 7.5 L H2O (g)
B. 15 L H2O (g)
C. 30 L H2O (g)
D. 45 L H2O (g)
E. 60 L H2O (g)
1
Expert's answer
2018-01-22T05:52:29-0500
1L 4L С3Н8 + 5О2 = 3СО2 + 4Н2О 15L x L 1L/15L = 4L/x L x=15*4 / 1=60 L E. 60 L H2O (g)
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment