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Answer to Question #71221 in General Chemistry for Fiona
Question #71221
The molecular mass of CaCO3 is 100 g/mol. How many moles of CaCO3 are in 38 kg of CaCO3?
Expert's answer
n(CaCO3)=m(CaCO3)/M(CaCO3)
n(CaCO3)=38000(g)/100(g/mol)=380mol
n(CaCO3)=38000(g)/100(g/mol)=380mol
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