Answer to Question #71098 in General Chemistry for Jeser correa

Question

Give two differences that you would observe in the electrolytic cell if copper electrode was made the anode and graphite electrode was made the cathode

Answer 1

(P1*V1) / T1 = (P2*V2) / T2
756 mmHg = 100791.432 Pa
508 mmHg = 67727.576 Pa
30 C = 303 K
-31 C = 242 K
(100791.432 Pa * 0.33 m3) / 303 K = (V2 * 67727.576 Pa) / 242 K
109.772 = V2*279.866
V2= 2.549 L
Answer:
V= 2.549 L