You will need to make four dilutions of the 0.40 M Cu(NO3)2 stock solution. determine the volume of Cu(NO3)2 stock solution and volume of H2O needed to make 10.00 mL of four solutions with concentrations between .200 M and 0.0250 M.
What threw me off here is that that the solution of H2O and CU(NO3)2 must be 10.00 mL.
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Expert's answer
2017-09-21T03:31:07-0400
0.200 M – 9.375 ml of 0.40 M + 9.375 ml of distilled water ↓ 8.75 ml 0.100 M – 8.75 ml of 0.200 M + 8.75 ml of distilled water ↓ 7.5 ml 0.050 M – 7.5 ml of 0.100 M + 7.5 ml of distilled water ↓ 5 ml 0.025 M – 5 ml of 0.050 M solution + 5 ml of distilled water
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