Answer to Question #70176 in General Chemistry for Daniel

General Chemistry

Question #70176

What is the energy of the electron in the n=1 level on an atom with an atomic number of 39?

Expert's answer

E(n=1) = - (m*e^4*Z^2)/(8e0^2*h^2*n^2) = - (9.1*10^-31kg*(1.6*10^-19C)^4*39^2)/(8*(8.85*10^-12F/m)^2*(6.62*10^-34Jsec)^2*1^2) = 3.3*10^-15 J

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