63.9 ml of 0.560 M sulfuric acid solution was completely neutralized by 28.3 ml of potassium hydroxide solution. What was the concentration of the potassium hydroxide?
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Expert's answer
2017-03-31T13:20:07-0400
Reaction of neutralization of sulfuric acid by potassium hydroxide: H_2 SO_4+2KOH=K_2 SO_4+H_2 O Using the Law of equivalence: n(H_2 SO_4 )=n(KOH) c(H_2 SO_4 )∙V(H_2 SO_4 )=c(KOH)∙V(KOH) c(KOH)=(c(H_2 SO_4 )∙V(H_2 SO_4 ))/V(KOH) =(63.6 ml∙0.560 M)/(28.3 ml)=1.259 M Answer: concentration of potassium hydroxide is 1.259 M.
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