63.9 ml of 0.560 M sulfuric acid solution was completely neutralized by 28.3 ml of potassium hydroxide solution. What was the concentration of the potassium hydroxide?
1
Expert's answer
2017-03-31T13:20:07-0400
Reaction of neutralization of sulfuric acid by potassium hydroxide: H_2 SO_4+2KOH=K_2 SO_4+H_2 O Using the Law of equivalence: n(H_2 SO_4 )=n(KOH) c(H_2 SO_4 )∙V(H_2 SO_4 )=c(KOH)∙V(KOH) c(KOH)=(c(H_2 SO_4 )∙V(H_2 SO_4 ))/V(KOH) =(63.6 ml∙0.560 M)/(28.3 ml)=1.259 M Answer: concentration of potassium hydroxide is 1.259 M.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment