Question

Determine the product when Th 234 90 undergoes two beta emissions ( e 0 1 ) followed by two alpha emissions ( He 4 2 ). Write nuclear equations for each of the four steps in the process. (You should show the isotopes formed by each step of the decay process).

Answer 1

The final product is Ra 226 88

Steps of the decay process:
1) Th 234 90 → Pa 234 91 + e 0 -1
2) Pa 234 91 → U 234 92 + e 0 -1
3) U 234 92 → Th 230 90 + He 4 2
4) Th 230 90 → Ra 226 88 + He 4 2