Answer to Question #65290 in General Chemistry for Sarah

Question

What mass of ethanol is needed to create 2.5 gram of ethanoic acid (CH3COOH)? assume the ratio of ethanol to ethanoic acid needed is 1:1

Answer 1

m(CH3CH2OH) = 2,5g
n(CH3CH2OH) : n(CH3COOH) = 1: 1
m(CH3COOH) = ?
X g 2.5g
CH3CH2OH → CH3COOH
46 g/moll 60 g/moll
46g (CH3CH2OH) ─ 60g (CH3COOH)
X g (CH3CH2OH) ─ 2,5g (CH3COOH)

2,5×46
60

X = = 1,92g.

Answer: 1,92g. (CH3CH2OH)