The average concentration of gold in seawater is 100 fM (femtomolar).
1)Given that the price of gold is $1764.20 per troy ounce (1 troy ounce = 31.103 g), how many liters of seawater would you need to process to collect $6000 worth of gold, assuming your processing technique captures only 50 % of the gold present in the samples?
The answer to the question is available in the PDF file https://www.assignmentexpert.com/https://www.assignmentexpert.com/homework-answers/chemistry-answer-62394.pdf
Comments
Leave a comment