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Answer to Question #59173 in General Chemistry for Noeli
Question #59173
what is the molarity of a HCl solution that contains 6.40g of HCl in 477mL of solution? answer in units of M
Expert's answer
M(HCl) = 35.5 + 1 = 36.5 (g/mol)
n(HCl) = m/M = 6.4 / 36.5 = 0.175 (mol)
c(HCl) = n / c = 0.175 / 0.477 = 0.37 (mol/l)
Answer
c(HCl) = 0.37 M
n(HCl) = m/M = 6.4 / 36.5 = 0.175 (mol)
c(HCl) = n / c = 0.175 / 0.477 = 0.37 (mol/l)
Answer
c(HCl) = 0.37 M
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