Answer to Question #57950 in General Chemistry for Armaan
A 41.1-mL sample of H2 at STP would contain how many grams of hydrogen?
The volume of 1 mole of gas under normal conditions is equal to 22.4 liters. The molar mass of hydrogen is equal to 2 g / mol. Thus, the weight of 22.4 liters of hydrogen is equal to 2 grams 41.1 mL = 0.0411 liters. Then the mass of 41.1 ml of hydrogen is 2 * 0.0411 / 22.4 = 0.00367 g = 3.67*10–3 g.
Answer. Weight of 41.1 ml of hydrogen is 3.67*10–3 g