77 367
Assignments Done
Successfully Done
In July 2019

Answer to Question #56363 in General Chemistry for Jasmine

Question #56363
Calcium carbonate decomposes to form calcium oxide and carbon dioxide on strong heating. What is the volume of carbon dioxide released, measured at r.t.p, when 10.5 g of calcium oxide is formed?
Expert's answer
CaCO3 = CaO + CO2
nCO2 = nCaCO3 = mCaCO3/MWCaCO3 = 10.5 g/100.0869 g/mol = 0.1049 mol;
VCO2 = nCO2*Vm = 0.1049 mol*24 L/mol = 2.5178 L ≈ 2.52 L

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


No comments. Be first!

Leave a comment

Ask Your question

Privacy policy Terms and Conditions