Answer to Question #56363 in General Chemistry for Jasmine
Calcium carbonate decomposes to form calcium oxide and carbon dioxide on strong heating. What is the volume of carbon dioxide released, measured at r.t.p, when 10.5 g of calcium oxide is formed?
CaCO3 = CaO + CO2
nCO2 = nCaCO3 = mCaCO3/MWCaCO3 = 10.5 g/100.0869 g/mol = 0.1049 mol;
VCO2 = nCO2*Vm = 0.1049 mol*24 L/mol = 2.5178 L ≈ 2.52 L