Answer to Question #56319 in General Chemistry for Tracy Guido
What would it look like and does a reaction occur:
Fe and HCl
Zn and HCl
Cu and HCl
Fe and HNO3
Cu and HNO3
Zn and HNO3
Iron and zinc force out hydrogen from hydrochloric acid:
Fe + 2HCl → FeCl2 + H2↑
Zn + 2HCl → ZnCl2 + H2↑
Copper is among tension after hydrogen therefore doesn't force out hydrogen from the diluted solution of a hydrochloric acid: Cu + HCl ≠ With the concentrated hot hydrochloric acid: 2Cu + 4HCl → 2H[CuCl2] + H2↑
With the diluted hydrochloric acid in the presence of oxygen and with a gaseous HCl at 500 — 600 °C: 2Cu + 4HCl + O2 = 2CuCl2 + 2H2O
At interaction of nitric acid of any concentration and the concentrated chamois with metals hydrogen is never emitted.
The concentrated cold nitric acid passivates iron: Fe + HNO3 ≠
When heating: Fe + 6HNO3(конц.)→ Fe(NO3)3 + 3NO2↑ + 3H2O
With the diluted nitric acid Fe + 4HNO3 = Fe(NO3)3 + NO↑ + 2H2O.
With the concentrated nitric acid:
With the diluted nitric acid:
With the concentrated nitric acid: Zn + 4HNO3 = Zn(NO3)2 + 2NO2↑+ 2H2O With the diluted nitric acid 4Zn + 10HNO3 = 4Zn(NO3)2 + NH4NO3 + 3H2O.