How much heat in kilocalories is required to vaporize 1.7 mol?
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Expert's answer
2015-11-16T10:00:34-0500
The heat of vaporization of water is 9.72 kcal/mol. We can calculate the heat is required to vaporize 1.7 mol of the water: Q = n (H2O) × C vapor.( H2O) = 1.7 mol × 9.72 kcal/mol = 16.524 kcal Answer: Q = 16.524 kcal
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