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Answer to Question #56314 in General Chemistry for Michaela

Question #56314
How much heat in kilocalories is required to vaporize 1.7 mol?
Expert's answer
The heat of vaporization of water is 9.72 kcal/mol. We can calculate the heat is required to vaporize 1.7 mol of the water:
Q = n (H2O) × C vapor.( H2O) = 1.7 mol × 9.72 kcal/mol = 16.524 kcal
Answer: Q = 16.524 kcal

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