Answer to Question #56158 in General Chemistry for sue
Rank the following in increasing order of their molarity.
Rank from lowest to highest. To rank items as equivalent, overlap them.
a. 63.0 g of NaOH dissolved in 1.0 L of water
b. 6.625 g of NaOH dissolved in 250. mL of water
c. 8.0 g of NaOH dissolved in 500. mL of water
d. .530 g of NaOH dissolved in 100 mL of water
c = n/V, where n - number of moles, V - volume of water in L.
n = m/M, where M - is a molar mass, m - is a mass in g.
C(NaOH) = m(NaOH)/(M(NaOH) V(water))
C (a) = 63/40 1 = 1.575 mol/L
C (b) = 6.625/40 0.25 = 0.663 mol/L
C (c) = 8/40 0.5 = 0.4 mol/L
C (d) = 0.53/40 0.1 = 0.133 mol/L
d - c - b - a
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!