# Answer to Question #56052 in General Chemistry for sue

Question #56052

When heated, KClO3 solid forms solid KCl and O2 gas. A sample of KClO3 is heated and 365 mL of gas with a pressure of 790 mmHg is collected over water, at 26 ∘C. At 26 ∘C, the vapor pressure of water is 25 mmHg: 2(KClO3)(s)→2(KCl)(s)+3(O2)(g)

Part A

What is the pressure of the dry O2 gas?

Express your answer with the appropriate units.

PO2 = ??

Part B

How many moles of O2 were produced?

Express your answer with the appropriate units.

n =

Part C

How many grams of KClO3 were reacted?

Express your answer with the appropriate units.

m = ???

Part A

What is the pressure of the dry O2 gas?

Express your answer with the appropriate units.

PO2 = ??

Part B

How many moles of O2 were produced?

Express your answer with the appropriate units.

n =

Part C

How many grams of KClO3 were reacted?

Express your answer with the appropriate units.

m = ???

Expert's answer

2KClO

Part A. The total pressure over water consist of the partial pressures of oxygen and water vapour:

P(total) = P(oxygene)+P(vapour);

P(oxygene) = P(total) - P(vapour) = 790 – 25 = 765 mmHg OR 1.007 atm OR 101992 Pa

Part B. The number of moles of oxygen can be calculated using the formula of ideal gas law converting the values to SI units - V = 0.000365 m

The number of moles using the selected equation is n = 0.015 mole.

Part C. The number of moles of KClO

The molar mass of KClO

The mass of KClO

Answer: 101992 Pa; 0.015 moles; 1.225 g

_{3}(s)→2KCl(s)+3O_{2}(g)Part A. The total pressure over water consist of the partial pressures of oxygen and water vapour:

P(total) = P(oxygene)+P(vapour);

P(oxygene) = P(total) - P(vapour) = 790 – 25 = 765 mmHg OR 1.007 atm OR 101992 Pa

Part B. The number of moles of oxygen can be calculated using the formula of ideal gas law converting the values to SI units - V = 0.000365 m

^{3}; T = 299.15 K; R = 8.314 J/(mol*K):The number of moles using the selected equation is n = 0.015 mole.

Part C. The number of moles of KClO

_{3}is 0.015x2/3 = 0.01 moleThe molar mass of KClO

_{3}is122.55 g/molThe mass of KClO

_{3}is m = nM = 0.01x122.55 = 1.225 gAnswer: 101992 Pa; 0.015 moles; 1.225 g

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