Answer to Question #56044 in General Chemistry for rachel
When 41.0 g of Mg reacts, what volume, in liters, of H2 gas is produced at 23 ∘C and 850 mmHg ?
Express your answer with the appropriate units.
V = nRT / P
n(H2) = n (Mg) = m (Mg) / M (Mg) = 41.0 g / (24.0 g/mol) = 1.7 mol
R = 62360 mmHg/mol*K
T = 23 ˚C + 273 = 296 K
V(H2) = (1.7 mol * 62360 mmHg / mol*K * 296) / 850 mm Hg = 36917.1 ml = 36.9 L
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