Answer to Question #55918 in General Chemistry for LK
4 NH3 + 5O2 →4 NO +6 H2O
From the reaction we can see that from 4 moles of ammonium we get 6 moles of water.
M(NH3) =17 g/mol;
M(H2O) = 18g/mol;
The mass of water which is produced by the reaction we can find from the following proportion:
2.76 g of NH3 – 4 mol * 17 g/mol
x g of H2O – 6 mol * 18g/mol
then x = 6*18*2.79/(4*17) = 4.38 g
The mass of water which is produced by the reaction is 4.38 g.
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