Question #55853

How many total atoms are in 0.270 g of P2O5?

Expert's answer

Each P2O5 molecule consists of 7 atoms (2P and 5O). Let's first calculate the amount of P2O5 molecules.

N(P2O5) = NA*n(P2O5), where n(P2O5) = m(P2O5)/M(P2O5) and NA is Avogadro constant and 6.022x1023 molecules/mol

N(P2O5) = NA*m(P2O5)/M(P2O5) = 6.022x1023*0.27/142 = 1.145x1021 molecules

So the total number of atoms is:

N(Atoms) = 7* N(P2O5) = 7*1.145x1021 = 8.015x1021 molecules

Answer : Total number of atoms is 8.015x1021 molecules.

N(P2O5) = NA*n(P2O5), where n(P2O5) = m(P2O5)/M(P2O5) and NA is Avogadro constant and 6.022x1023 molecules/mol

N(P2O5) = NA*m(P2O5)/M(P2O5) = 6.022x1023*0.27/142 = 1.145x1021 molecules

So the total number of atoms is:

N(Atoms) = 7* N(P2O5) = 7*1.145x1021 = 8.015x1021 molecules

Answer : Total number of atoms is 8.015x1021 molecules.

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