Answer to Question #55746 in General Chemistry for Nicole

Question

What mass of calcium carbonate in grams will be produced from 1.67 mole of sodium carbonate

Answer 1

Ca(OH)₂(aq) + Na₂CO₃ (aq) = CaCO₃(s) + 2NaOH(aq)
From the stoichiometry of this reaction it is obviously that 1 mole of sodium carbonate yields to 1 mole of calcium carbonate, so
n(CaCO₃) = n(Na₂CO₃) = 1.67 mol
The relationship between the amount of substance and the mass is as follows:
m(CaCO₃) = n(CaCO₃) M(CaCO₃)
m(CaCO₃) = 1.67x100.09 = 167.15 g

Answer: 167.15 g