Answer to Question #55727 in General Chemistry for sue

Question

The gaseous hydrocarbon butane, C4H10, burns according to the following equation:
2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g)

If the reaction in part c produces 130 g of CO2, what is the percent yield of CO2 for the reaction?
Express your answer with the appropriate units.
The percent yield of CO2 = ???

Answer 1

Percent yield = actual yield / theoretical yield * 100%
Actual yield (CO₂) = 130 g
Theoretical yield (CO₂) = 168.7 g
Percent yield (CO₂) = 130 g / 168,7 g * 100% = 77 %.