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Answer to Question #55727 in General Chemistry for sue

Question #55727
The gaseous hydrocarbon butane, C4H10, burns according to the following equation: 2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g) If the reaction in part c produces 130 g of CO2, what is the percent yield of CO2 for the reaction? Express your answer with the appropriate units. The percent yield of CO2 = ???
Expert's answer
Percent yield = actual yield / theoretical yield * 100%
Actual yield (CO2) = 130 g
Theoretical yield (CO2) = 168.7 g
Percent yield (CO2) = 130 g / 168,7 g * 100% = 77 %.

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