Answer to Question #55703 in General Chemistry for sue

Question #55703
The gaseous hydrocarbon butane, C4H10, burns according to the following equation: 2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g) How many grams of O2 are needed to react completely with 23.5 g of C4H10? Express your answer with the appropriate units. m(O2) = ????? Thank you so much!!
1
Expert's answer
2015-10-21T03:31:14-0400
2C4H10(g) + 13O2(g) → 8CO2(g) + 10H2O(g)

m(O2) = M(O2)*n(O2)
n(O2) = (13/2)*n(CO2) = (13/2)*(m(CO2)/M(CO2)) = (13/2)*(23.5/58) = 2.63 mol
m(O2) = M(O2)*n(O2) = 32*2.63 = 84.28 g

Answer : m(O2) = 84.28 g

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