Answer to Question #55669 in General Chemistry for rachel

Question

The gaseous hydrocarbon butane, C4H10, burns according to the following equation:
2C4H10(g)+13O2(g)→8CO2(g)+10H2O(g)
How many moles of H2O are produced from the complete reaction of 2.00 mol of C4H10?
Express your answer with the appropriate units.

Answer 1

2C₄H₁₀ (g) + 13O₂ (g) → 8CO₂ (g) + 10H₂O (g)
n(H₂O) = 5*n(C₄H₁₀) = 5*2 mol = 10 mol

Answer : 10 mol of H₂O