Answer to Question #55598 in General Chemistry for susan
A gas expands and does 82.7 J of work on the surroundings. At the same time, the gas loses 103 J of energy to the surroundings as heat. What is the change in the internal energy of the gas?
Would this be ΔE = q + w (-103) + (82.7) = -20.3. I get confused with the positive and negative charges.
Internal energy of gas ΔU = Q + W consists of work that is done and heat that is lost. Gas loses 82.7 J of energy in form of work and 103 J in form of heat. Finally, ΔU = Q + W = -82.7 – 103 = -185.7 J Gas loses 185.7 J of energy.