Answer to Question #54723 in General Chemistry for bower

Question #54723

what is the oxidation state of iodine in iodate ion?

Expert's answer

Iodate ion: empirical formulae is IO3-
The oxidation state of Oxygen is equal to -2. Then with easy calculation we get the oxidation state of iodine:
Ox(I) + Ox(O)*3 = -1
OX(I) = -1 - (Ox(O)*3) = -1 +2*3 = 5

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