# Answer to Question #54629 in General Chemistry for Janea

Question #54629

Find the number of joules needed to heat 37grams of water 78 degees C.

Expert's answer

To heat 1 g on 1 degree C we need 1 cal.

So to heat 37 g on 78 degrees C we need:

C=37*78=2886 cal.

1 cal.=4.184 J

So, 2886 cal.=2886*4.184=12075.024 J.

So to heat 37 g on 78 degrees C we need:

C=37*78=2886 cal.

1 cal.=4.184 J

So, 2886 cal.=2886*4.184=12075.024 J.

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