# Answer to Question #54304 in General Chemistry for prudence david

Question #54304

A proton with speed v perpendicular to a magnetic field B is experiences a force F. if the speed of the proton is doubled, the new force is

Expert's answer

The force acting on the moving charged particle with the velocity v and charge q is: F=qvB

Then, doubling the velocity leads doubling the force.

Then, doubling the velocity leads doubling the force.

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