Answer to Question #345909 in General Chemistry for Guy

Question

Given the Equation 6K + B2O3. 3K2O + 2B

How many grams of K2O will be produced whe you react one 3.5 g of B2O3

Answer 1

Solution:

The molar mass of B₂O₃ is 69.63 g/mol

Therefore,

Moles of B₂O₃ = (3.5 g B₂O₃) × (1 mol B₂O₃ / 69.63 g B₂O₃) = 0.05026 mol B₂O₃

Balanced chemical equation:

6K + B₂O₃ → 3K₂O + 2B

According to stoichiometry:

1 mol of B₂O₃ reacts with 3 mol of K₂O

Thus, 0.05026 mol of B₂O₃ react with:

(0.05026 mol B₂O₃) × (3 mol K₂O / 1 mol B₂O₃) = 0.15078 mol K₂O

The molar mass of K₂O is 94.2 g/mol

Therefore,

Mass of K₂O = (0.15078 mol K₂O) × (94.2 g K₂O / 1 mol K₂O) = 14.2035 g K₂O = 14.2 g K₂O

Mass of K₂O = 14.2 g

Answer: 14.2 grams of K₂O will be produced