Answer to Question #252206 in General Chemistry for Lyka

Question

Base on the stoichiometry road map calculate the problem below by showing the step by step solution.

Given the following reaction:

Al₂ (SO₄)₃ + 6 NaOH --------> 2 Al(OH)₃ + 3 Na₂SO₄

What mass of Al(OH)₃ is produced if 22.7 g of NaOH is consumed?

Answer 1

v(NaOH)=22.7/40=0,5675mol

v(Al(OH)4)=0.5675/3=0.19mol

m(Al(OH)3)=0.19*78=14.82g