Answer to Question #237498 in General Chemistry for boi

Question

1.    How many atoms of carbon are there in 0.40 mol of procaine, C₁₃H₂₀N₂O₂, a “pain killer” used by dentists?

Answer 1

1 mole of procaine contains $6.022\times 10^{23}molecules$

0.4 mole of procaine contains $0.4\times6.022\times 10^{23} molecules$

Therefore, 0.4 mol of procaine contains $\times 6.022\times 10^{23}\times 13$ atoms of carbon $=3.1\times 10^{24}$

atoms of carbon.