Answer to Question #229914 in General Chemistry for Parth

Question #229914

4gm of lead nitrate reacts with 1.17g of sodium chloride and form 3gm of lead chloride how much odium nitrate will form?


1
Expert's answer
2021-08-27T02:31:34-0400

2NaCl (aq) + Pb(NO3)2 (aq) → PbCl2 (s) + 2NaNO3 (aq)

"Moles (NaCl)=\\frac{1.17}{58.44}=0.02moles"


Ratio of "NaCl" and "NaNO_3" is 1:1


Hence


"Moles (NaNO_3)=0.02moles." 4gm


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