Answer to Question #228503 in General Chemistry for Kolly

Question

At s.t.p,a certain Mass of gas occupies a volume of 800cm3. Find the temperature at which the gas occupies 1000cm3 and has a pressure of 720mmhg

Answer 1

Let P1,V1 be the initial pressure,voloume and temparature of the gas at T1=273.15 and P2,V2 be the final pressure,voloume of tha gas T2 is the final temparature.

Use the combined gas law:

P1V1/T1 = P2V2/T2, where;

P1 = initial pressure = 720mmHg

V1 = initial volume = 800 cm3

P2 = final pressure = 720mmHg

V2 = final volume = 1000cm3

T1 = intial temperature = 273.15 K

T2=final temperature=?

Rearrange the equation for the combined gas law to isolate T2

T2 = P2V2T1/V1P1

T2=(720mmHg ×1000cm3 × 273.15k)/(800cm3 ×720mmHg)

T2=341.44K

So the gas occupies 1000cm3 and has a pressure of 720 mmHg at temperature 341.44K